Glofell's Current Divider Calculator computes branch currents in parallel circuits using the current divider rule. Enter up to 10 resistor values for fast, reliable results.

Introduction
Parallel circuits in which the source or supply current divides into a variety of parallel paths are known as current divider circuits. Both of the components in a parallel wired circuit have their terminals connected together and share the same two end nodes.
Parallel circuits are distinguished by the fact that, although different currents can flow through different branches, the voltage is shared by all linked paths. VR1 = VR2 = VR3... and so on. As a result, finding individual resistor voltages is no longer necessary, and branch currents can be easily calculated using Kirchhoff's Current Law (KCL) and, of course, Ohm's Law.
The current flowing through any branch of a parallel circuit can be calculated using this Current Divider Calculator.
When a circuit is connected in parallel, the total current from the power source is divided among the circuit's branches depending on the resistance values of each branch. Since current follows the path of least resistance, more current will flow through branches with lower resistance, while less current will flow through a branch with high resistance.
Understanding how current splits in a parallel circuit is essential for effective circuit design. Our calculator applies the standard Current Divider Rule to simplify this process for you.
To find the current flowing through a specific branch, we use the following equation:
Where:
The unit of this calculator's result is the one stated. Amperes (A), milliamperes (mA), or microamperes (A) may be used to express the resultant value.
A current divider is a parallel circuit where the total current entering a node splits among multiple branches, each with the same voltage. Current division refers to using Kirchhoff's Current Law (KCL)—the sum of currents entering a node equals the sum leaving it—to calculate the individual branch currents.
The current divider rule applies to parallel circuits, where the current divides among branches and the voltage across each branch is equal. It calculates the current through a given branch based on its resistance relative to the total parallel resistance. Similarly, the voltage divider rule applies to series circuits, where voltage divides according to resistance.
A voltage divider uses two resistors in series to produce an output voltage that is a fraction of the input voltage. The formula is V_out = (R_b / (R_a + R_b)) × V_in, where R_a and R_b are the two series resistors and V_in is the supply voltage.
Using Ohm's Law, current can be calculated as I = V ÷ R, where I is the current in amperes, V is the voltage in volts, and R is the resistance in ohms. For power, you can use P = V × I, which gives power in watts.
Yes, a voltage divider affects current. The current drawn by the load must also flow through the series resistor, which can change the output voltage. Because of this, voltage dividers are not suitable for supplying power to loads; they work best for low-current reference signals.
Yes. A parallel circuit has multiple paths for current to flow. The total current entering the circuit divides among these paths based on the resistance of each path—lower resistance receives more current, and higher resistance receives less.
In a parallel circuit, each branch has the same voltage, so you can calculate the current in each branch by dividing the supply voltage by that branch's resistance: I_branch = V / R_branch. The total current is the sum of all branch currents.
The voltage divider equation is V_out = V_in × (R2 / (R1 + R2)) for two series resistors R1 and R2. The output voltage is taken across R2, and the sum of the voltage drops across both resistors equals the supply voltage (Kirchhoff's Voltage Law).
To measure current, a multimeter must be connected in series with the branch so the current flows through it. Parallel-connected devices share the same voltage, but each may carry a different current, so measuring current in parallel would not give a meaningful reading.
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